Question

Need help with matrix problem. Check pic

Answer 1

So first you set up the matrix that represents that system. Then we actually have to do row operations >.< do you know what the row operations are?

Answer 2

Alright I set up the matrix system the same as before.

Answer 3

But don't remember row operations

Answer 4

just down the line?

Answer 5

as in 6 0 1 -9 ?

Answer 6

alright. there are 3 row operations we can do. and basically it mirrors elimination.
1) we can swap two rows.
2) we can multiply an entire row by a number (formally referred to as a scalar, technical jargon)
3) we can add a multiple of one row to another row.

Answer 7

and the goal is to get the matrix to look like:
1 0 0 a
0 1 0 b
0 0 1 c
This will tell us that x = a, y = b, and z = c (a b and c will be numbers)

Answer 8

oh there are different variables. I need to pay attention to that

Answer 9

okay

Answer 10

let me see if i can upload pics now ( i couldnt earlier) i'll write out some of the row operations and post it.

Answer 11

cool thank you

Answer 12

test >.>

Answer 13

I had to upload twicve before it worked

Answer 14

woo, we are good, alright give me a sec.

Answer 15

nice picture lol btw I believe you are more helpful than my actual teacher lol

Answer 16

its the one on one feeling lol. i didnt complete the process (mainly because i hate fractions and thats what pops up when doing this), but hopefully i showed enough of the process. One sec, its scanning.

Answer 17

okay thanks

Answer 18

Alright, heres the terminology i use when describing what row operation Im doing, and to what rows im doing it to. The first is a row swap. Second is multiplying a row by a scalar, and the third is adding a multiple of one row to another.

Answer 19

im going to be writing out the matrix over and over, and in between each one you will see one of those three operations. Thats letting the reader know what I did.

Answer 20

okay

Answer 21

alright made it through that part

Answer 22

man these matrixes are messing me up...lol elimination or substitution seem so much easier

Answer 23

haha figured it out! thanks man

Answer 24

sry for leaveing abruptly, I got company right when i posted the pictures >.<