Answer to if f(x)=-2x+8 and g(x)=√x+7, what is (f*g)(2)?
\[\sqrt{(-2x+8)+7}\] feeling pretty good of that one
i don't remember the (FoG) formula. can someone please remind me?
to find (f o g) you take your x in g and replace it with the function f if i remember correctly
why are there parenthesis?
just to show you the substitution made
g(2)=3 f(3)=-2(3)+8=2
So if I remove them it's still fine?
@lalay that looks better, what did you do?
awww 8(
nothing against you or your answer, I just don't think that's correct, and I don't want to submit it and find out if it is or isn't unless everyone is sure. And I haven't had a radicle at all before for these problems.. I'm sorry, idk which is right.
I can go ahead and check though.. Might as well.
first g(2) = sqrt 2+7 = sqrt 9 =3 then f(g(2))=f(3) = -2*3 +8 =2
Idk what to do :(
The first answer was incorrect.. I have a new question now?
(f*g)(2) = f(g(2)) so first u find g(2) u substitiute 2 in g(x) which is sqrt 9 =3 then f(g(2)) = f(3) u substitute 3 in f(x) whats ur question
If f(x)=-7x+2 and g(x)=√x+3, what is (f*g)(-2)
g(-2) = sqrt 1 = 1 f(g(-2)) = f(1) = -7+2 = 5
How do I solve f(g(-2)) = f(1) = -7+2 = 5?
since g(-2) = 1 then f(g(-2)) = f(1) u jus replace g(-2) bye its value which is 1 thn substitute 1 in f(x) u get -7(1)+2 = -5
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