If a stone is tossed from the top of a 330 meter building, the height of the stone as a function of time is given by h(t) = -9.8t2 – 10t + 330, where t is in seconds, and height is in meters. After how many seconds will the stone hit the ground? Round to the nearest hundredth’s place; include units in your answer. Show the work. I have tried the quadratic formula, factoring, and completing the square, but no such luck...Please help me!!
It does not factor. Hold on. Let's try the quad formula.
Or use the calculator. I get x = 5.32 secs. Is that right?
Use quad formula. You get x = 10 +/- sqrt(100-4(-9.8)(330)) all over -19.6
That simplifies to 10 +/- sqrt(13036) over -19.6
I didn't get that answer using the quad formula \[-b +-\sqrt{(b)^2 - 4ac} / 2a
Ignore the negative answer. You get (10-114.1753)/-19.6 = 5.315066521 or about 5.32 to the nearest hundredth. How's that look?
oh I can really ignore the negative answer?!
Yes, because time can't be negative
right thanks so much!!
The domain in this problem is x greater than or equal to 0
You're welcome. How 'bout a medal?
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