Question

the ave. of X numbers is 5. If Y is added to each number, the ave. will be?

Please answer clearly and explain the solution clearly and easy to understand. Thanks!
(guaranteed medal for a good answer)

Answer 1

Not again...!

Answer 2

you explained this already estudier but i forgot it

Answer 3

i just have a question

Answer 4

Hi moongazer,

Average is sum/number, if you increase sum by 5y and divide by 5, then average is 5+y.
(this is your answer before)

my question is:
could you make an equation as an explanation for this?
not like the \[\sum_{?}^{?}\] equation)

Answer 5

but if it easier to understand with that you may ^_^

Answer 6

sorry for asking this question again :)

Answer 7

Just do some algebra

(a+b+c+d+e)/5 = 5 by definition of average.

Then (a+b+c+d+e) = 25

(a+Y + b +Y +....) = 25 + 5Y so

average is (25 +5Y)/5 = 5+Y

Answer 8

U cannot make it any clearer than that...

Answer 9

why you divided it by 5?
(a+b+c+d+e)/5 = 5 by definition of average.

Answer 10

by definition of average.

Answer 11

The average is the sum divided by the number of items

Answer 12

why is it it is 5? but the question says "X numbers"
so the number of terms is X?

Answer 13

I was using the answer I gave u as an example the last time to answer your question.

Replace 5 with X and use...'s

Answer 14

(a+b+c+d+e)/X = 5 by definition of average.
Then (a+b+c+d+e) = 5X

(a+Y + b +Y +....) = 5X + 5XY so average is (5X +5XY)/X = 5+Y

Answer 15

Got it, now?

Answer 16

Wait, mistake...

Answer 17

(a+Y + b +Y +....) = 5X + XY so average is (5X +XY)/X = 5+Y

Answer 18

I left the 5 in...