Question

Keep all answers in fractional form. Solve the systems of equations. y=2x-5, y=6x+7

Answer 1

http://www.wolframalpha.com/input/?i=y%3D2x-5%2C+y%3D6x%2B7

Answer 2

You have 2 equations where y = something. Since they both equal y, that also means they equal each other: i.e. \(2x-5 = 6x+7\), so you can just solve for x using algebra. Then you can find y by plugging x into one of the original equations.

Answer 3

systems of equations is a bit of a step up from the other stuff you were doing ...

Answer 4

the most basic solution would be to solve for one variable and use that in the other equation

Answer 5

Yeah... i think this homework is just going to keep on getting harder. But how do i solve for one variable if there is two variables in the equation?

Answer 6

y=2x-5 ; well, its already solved for y so I spose that part was redundant, so lets substitute this value in the other equation where it has a y

y=6x+7

2x-5 = 6x+7 ; now all we have to do is solve for x

Answer 7

try to express y in terms of x. or x in terms of y. then substitute.

Answer 8

would the answer be -3?

Answer 9

That is the value of x, yes! Now find the value of y by plugging the x into one of the original equations.

Answer 10

dunno lets chk:

2x-5 = 6x+7 ; lets +5 to each side
+5 +5
-------------
2x+0 = 6x+12 ; now we can subtract 6x from each side
-6x -6x
---------------
-4x+0 = 0+12 ; and lets re write it to clean it up

-4x = 12 ; the only thing left to do is divide out the -4
/-4 /-4
--------
x = -3 ; that is the solution for x, now that we have a solid
answer we can use it in our original equations to find y

Answer 11

uh, would it be -11? because
y=6x+7
y=6(-3)+7
y=-18+7
y=-11..right?

Answer 12

since x=-3

y=2x-5
= 2(-3) -5
= -6 -5
= -11

OR

y =6x+7
=6(-3)+7
= -18 + 7
= -11

from the looks of it; when x=-3; y=-11

Answer 13

Yess! I did it right! :D

Answer 14

great job :)