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-3x^2 - 5x +12 = 0 How to solve for x?
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quadratic formula will do it. do you know it?
I do but I am getting the wrong answer for some reason?
\[-b \pm \sqrt{b ^{2}-4ac}/2a\] a = -2 b = -5 c = 12
you should get two possible values for x
actually a = -3
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I will try it again.
miss-keyed
\[x=\frac{5\pm\sqrt{3^2-4\times -3\times 12}}{2\times -3}\] is a start
yeah i make typos all day and it is a pain to rewrite!
\[x=\frac{5\pm\sqrt{9+144}}{-6}\] \[x=\frac{5\pm\sqrt{153}}{-6}\]
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or if you prefer \[x=\frac{-5\pm\sqrt{153}}{6}\]
What would i do after that step?
this is the point where i screw up
\[x = (-5\pm 12.369)/ 6\]
what is the final answer supposed to be because according to my answer sheet it is x= 4/3
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