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Mathematics 21 Online
OpenStudy (anonymous):

-3x^2 - 5x +12 = 0 How to solve for x?

OpenStudy (anonymous):

quadratic formula will do it. do you know it?

OpenStudy (anonymous):

I do but I am getting the wrong answer for some reason?

OpenStudy (anonymous):

\[-b \pm \sqrt{b ^{2}-4ac}/2a\] a = -2 b = -5 c = 12

OpenStudy (anonymous):

you should get two possible values for x

OpenStudy (anonymous):

actually a = -3

OpenStudy (anonymous):

I will try it again.

OpenStudy (anonymous):

miss-keyed

OpenStudy (anonymous):

\[x=\frac{5\pm\sqrt{3^2-4\times -3\times 12}}{2\times -3}\] is a start

OpenStudy (anonymous):

yeah i make typos all day and it is a pain to rewrite!

OpenStudy (anonymous):

\[x=\frac{5\pm\sqrt{9+144}}{-6}\] \[x=\frac{5\pm\sqrt{153}}{-6}\]

OpenStudy (anonymous):

or if you prefer \[x=\frac{-5\pm\sqrt{153}}{6}\]

OpenStudy (anonymous):

What would i do after that step?

OpenStudy (anonymous):

this is the point where i screw up

OpenStudy (anonymous):

\[x = (-5\pm 12.369)/ 6\]

OpenStudy (anonymous):

what is the final answer supposed to be because according to my answer sheet it is x= 4/3

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