Solve the following system of equations.

x + 4y + z = –10
3x – 3y + 6z = –21
x + 2y + 2z = –10
Answer
(–4, –1, –2)
(2, –2, –4)
(–3, –2, –3)
(1, –2, –3)

Question

Solve the following system of equations.

x + 4y + z = –10
3x – 3y + 6z = –21
x + 2y + 2z = –10
Answer    
 (–4, –1, –2) 
   (2, –2, –4) 
   (–3, –2, –3) 
   (1, –2, –3)

anonymous · Answer

Didn't you ask this already?

anonymous · Answer

yeah but i need help

anonymous · Answer

Yeah, but we were helping you and you left..

anonymous · Answer

So I'll ask again. Do you want help, or just the answer?

anonymous · Answer

And again you seem to have left...

anonymous · Answer

help to the answer so kinda both

anonymous · Answer

So what do you get if you subtract 3 times the 3rd equation from the second one?

anonymous · Answer

let me ask you this, what kind of math are you in david?

anonymous · Answer

x + 4y + z = –10
3x – 3y + 6z = –21
x + 2y + 2z = –10
(1  4  1  -10)
(3  -3  6  -21)
(1  2  2  -10)
have you ever seen this type of notation david?

anonymous · Answer

algebra2

anonymous · Answer

ok do you see the first and third eq have the same answer -10.  set those two equal to eachother and isolate one variable

anonymous · Answer

x+4y+z=x+2y+2z
z=2y

anonymous · Answer

okey then what

anonymous · Answer

ok what you need to do is 1st pick two eq's solve for two variables and solve that.  then pick two others and solve for one new variable and one old one.  then sub those back in to solve the equations.  its really hard to do it on this site.  there should be an equation in algebra 2 that does this an easier way than elimination.  but since they gave you the answers maybe they have not shown you how to solve for these things yet.