Question

what is x in x^2-sinx=0 ?

Answer 1

can this be answered?

Answer 2

yeah it has two answers here it is check out
http://www.wolframalpha.com/input/?i=x%5E2-sinx%3D0

Answer 3

one root is x=0 as sin 0 = 0

Answer 4

jimmrep i think ur wrong cause u cannot neither factor x and nor u can equal them to zero

Answer 5

so it has no answer?

Answer 6

Jimmyrep is right. Plug in zero, it is a solution.

Answer 7

yup = retricesimple as that

Answer 8

chakaron. It has to have an answer. Lol. http://www.wolframalpha.com/input/?i=x^2-sin(x)%3D0 It has two. As stated in the fundamental theorem of algebra. An n order polynomial is guaranteed to have n solutions.

Answer 9

it is order 2 - so 2 solutions

Answer 10

oh. right. thanks.=)

Answer 11

uhm. is there a step by step solution for this? i don't get why the other x has a value?..

Answer 12

Consider this:
\[x^2-\sin(x)=0 \implies x=\pm \sqrt{\sin(x)}\]
Graph y=x, y=sqrt(sin(x)),y=-sqrt(sin(x))
You'll find two intersection points. Those are the solutions.
Just pay attention to the top graph. The second one won't have any meaning for you.
http://www.wolframalpha.com/input/?i=plot+y%3Dx%2C+y%3Dsqrt%28sin%28x%29%29%2Cy%3D-sqrt%28sin%28x%29%29

Answer 13

ok. thanks. but still I'm confused with the main problem: y=x^2 and y=sinx. Find the area.