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f(x)=1 , f(x+h)-f(h) h doesnot equal 0 ___x _________ 2 h
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?
oh i see \[f(x)=\frac{x}{2}\] maybe ? and you want \[\frac{f(x+h)-f(x)}{h}\] is that it?
yes it is
except that the second part is f(h) not f(x)
that is a typo i bet
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honestly, i wouldnt know....thats whats on my packet lol
wait your right just looked at it sorry
of course i am right. this is the "difference quotient." you write \[\frac{\frac{x+h}{2}-\frac{x}{2}}{h}\]
then some algebra to get \[\frac{x+h-x}{2h}\] and finally just \[\frac{1}{2}\] i.e the slope
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