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Which is an equation of the line passing through points at (1, 6) and (-2, 1)? y = 2x + 5 y = 5/3x + 13/3 y = x + 5 y = -1/2x +13/2
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Try getting the slope of the line first, using the formula: \[m=\frac{y_2-y_1}{x_2-x_1}\]
The slope is -5/3
i mean -5/-3
Great, that's what I got as well. Those minus signs will cancel each other out too, and you'll have \(\frac{5}{3}\) as the slope. The next step is to plug some numbers into the equation for a line, which is: \(y-y_1 = m(x-x_1)\)
so the answer is y = 5/3x + 13/3
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That's what I got, and it matches up to option B above. Congrats on getting it right!
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