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Solve the system, using substitution. Show work please! thanks! (a,b). a + b = 4 and 2a + 3b = 11
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In your first equation, solve for either variable. Then substitute what you get from that, into the second equation. Should become obvious from there.
a=4-b substitute a in 2nd equation
Yes what they said... make your other equation 2(4-b)+3b=11
So that will become 8-2b+3b=11
Simplify that into 8+b=11
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that turns into b=3
Now take your value for b and substitute it into the equation
2(4-b)+3b=11 8-2b+3b=11 8+b=11 b=3
a+(3)=4
a=1 so b=3 and a=1
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