Solve the system by using elimination or elimination with multiplication.
2x + 3y = 12 and 3x + 2y = 13

(3, 2)
(-3, 2)
(-3, -2)
no solution
infinitely many solutions

Question

Solve the system by using elimination or elimination with multiplication.
2x + 3y = 12 and 3x + 2y = 13
 
    (3, 2) 
   (-3, 2) 
   (-3, -2) 
   no solution 
   infinitely many solutions

anonymous · Answer

in this case it is easiest just to check the solutions provided.  plug in the numbers and see if they work

anonymous · Answer

only real chance is for the first one.  try 
$$2\times 3+3\times 2=6+6=12$$ 
$$3\times 3+2\times 2=9+4=13$$ so first one it is

radha · Answer

multiply the first eqn with 3...and the second one with 2...then eliminate...!

radha · Answer

you will get 6x+9y=36.......6x+4y=26
now by solving by subtracting 2nd eqn from 1st....we get y=2 and x=3....so first option is correct