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Mathematics 13 Online
OpenStudy (anonymous):

Find the 10th term of the sequence 2, 6, 18, 54, 162

OpenStudy (sriram):

162+324=486

OpenStudy (sriram):

differences are in GP

OpenStudy (anonymous):

what would the 10th term be thought?

OpenStudy (sriram):

i m gettin 39368

OpenStudy (anonymous):

n=the term 2*3^(n-1) 2*3^(10-1) Solve! From what the numbers looked like, it seemed the number was multiplied by 3 over and over again. The starting number is 2, so it's 2 times 3 by the power of whatever. The notation needs to subtract by 1 because: \[2\times3^{0}=2\] (1st term) \[2\times3^{1}=6\] (2nd term) \[2\times3^{2}=18\] (3rd term) Notice the exponent by the 3 is one before the term.

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