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The initial term and common difference are given. What is the nth term of the arithmetic sequence? a1 = 6; d = (-2)
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This is pretty much the same deal as before: a(n) = C + dn Where we can find C because a(1) = 6, Therefore 6 = C + -2 What is C?
would it be 6-2n?
It cannot be because a(1) = 6, so that means 6 = 6 - 2 which isn't true.
It must be that C is 2 less than 6
heres my possible answers 8 - 2n 6 - 2n none of these 4 - 2n
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And which of those has a 'C" that is 2 less than 6?
none
I'd argue that 4 is 2 less than 6
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