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Anyone good with log properties? If ln(3x+5) + ln(3x-5) = 6 + ln4 I can use prop 4 to get ln(3x+5)(3x-5)=6+ln4 Does (3x+5)(3x-5)=10?
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i would write \[\ln(3x+5)+\ln(3x-5)-\ln4=6\] and use properties to write ln(a)+ln(b)-ln(c) as ln(a*b/c)
and I would write \[6 \] as \[\ln(e^6)\]
so then you would have \[\frac{a*b}{c}=e^6\] see if you can figure it out from here let me know if you have any questions
I set it up like that, but I still don't understand what happens next.... what do I do with the e?
what do you mean its just a number like 5 or 3.4422 or 2 you want to solve for x
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\[\frac{(3x+5)(3x-5)}{4}=e^6\]
\[(3x+5)(3x-5)=4e^6\] \[(3x+5)(3x-5)=4e^6\] \[9x^2-25=4e^6\] \[9x^2=4e^6+25\] you try the rest
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