Question

solve 2(x+3)^2=49

Answer 1

First you could simplify the equation. Remember PEMDAS. Parenthesis, Exponent, Multiply, Divide, Add and Subtract.
So first square the binomial.
\[2(x ^{2}+6x+9)= 49\]
Then distribute the value 2 or multiply this to the polynomial.
\[2x^2+12x+18=49\]
Then simplify and transpose the value of 49 to the other side, making it negative.
\[2x^2+12x-31=0\]

Answer 2

oh no !

Answer 3

a thousand times no
do not multiply out
do not facor
do not use the formula!

Answer 4

o.O Jeez sorry.

Answer 5

this problem is set up for you to solve just as it is! please do not do all that stuff

Answer 6

\[2(x+3)^2=49\]
\[(x+3)^2=\frac{49}{2}\]
\[x+3=\pm\sqrt{\frac{49}{2}}=\pm\frac{7}{\sqrt{2}}\]

Answer 7

and so
\[x=-3\pm\frac{7}{\sqrt{2}}\]

Answer 8

Well it just said Solve. He didnt say anything about getting this or that or the vertex form or whatever. So, just made it in the standard form. My bad. Sorry. -.-

Answer 9

it is already a perfect square so you do not want to multiply out and then complete the square again