Question

wouldn't it be cool if openstudy was easy to access on iphone?

Answer 1

Cool indeed; also a lot of work. It's in the plan, though!

For now, it should be reasonably easy to use, if a bit small. Remember that to scroll the left pane or chat, you can use two fingers (instead of the usual one-finger scroll). Other than that, everything else should work normally, albeit probably a little slowly.

Answer 2

openstudy can be access on iphone
but from my experience it is hard to type
whenever you start typing you have to type blind because it makes that part of the page go up
i have answered some questions iphone but only some because it gets annoying lol
but thats cool it is in the works
also shadow i know this isn't the math section, but I can show you a proof by uploading it here if you like
the proof is on proving the quadratic formula and also you can use the process to factor quadratics

Answer 3

Yeah, the issue with the moving of the page *should* actually be fixed as of the deploy half an hour ago. I haven't double-checked yet, though.

Answer 4

k

Answer 5

Yeah, it's still a bit slow, but it doesn't jump you around anymore.

Answer 6

Hm. Seems odd. The definitions of b and ac in particular seem to come out of nowhere?

Answer 7

oh wait what

Answer 8

Which part? Haha.

Answer 9

out of nowhere?

Answer 10

Well, the definition of b obviously makes sense. But the leap to define ac as \((\frac{b}{2} + z)(\frac{b}{2} - z)\) is unclear to me.

Answer 11

ok the thing is we want to find two factors of a*c that have product a*c and add up to be b

Answer 12

i'm sorry this page did not explain all of that

Answer 13

i seen a pattern
based on the pattern i seen
i said well we
always want b to be in the form
b=(b/2+z)+(b/2-z)
and
we want a*c to be in the form
a*c=(b/2+z)(b/2-z) but here we can find what z by solving this equation

Answer 14

but we don't do anything with the a*c after point it is only to determine z

Answer 15

so we replace bx with
(b/2+z)x+(b/2-z)x
and then factor by grouping

Answer 16

would you like me to show you an example?

Answer 17

if you like you can choose any quadratic you like and i will factor it using this way

Answer 18

i can factor over the complex numbers too
so any quadratic you dream about

Answer 19

here is an example i did earlier

Answer 20

The one thing I'm worried about is whether you're already working backwards from the quadratic formula (in which case it's inevitable that you'll end up at the quadratic formula).

Answer 21

Or do you have a formal proof for why b and ac must both be related by z that *doesn't* involve the quadratic formula?

Answer 22

shadow are you still unclear about the a*c part
have you ever seen this before
3x^2+5x-2
a=3
b=5
c=2
a*c=3(-2)=-6
we want to find two factors of a*c that add up to be b
a*c=-6=6(-1)
b=6+(-1)
so 3x^2+6x-1x-2
now factor by grouping
3x(x+2)-(x+2)
(x+2)(3x-1)

so we can also it my way
a=3
b=5
c=-2

----
b=(5/2-z)+(5/2+z)

a*c=-6=(5/2-z)(5/2+z)=25/4-z^2
so z^2=25/4+6
so
z=sqrt{25/4+6}=sqrt{49}{4}=7/2

so we have b=(5/2-7/2)+(5/2+7/2)=-1+6
so its the same just weirder
this trick is only cool because it allowed me to find away to factor over complex numbers

Answer 23

Ah yes, so this is starting off of the concept of completing the square.

Answer 24

Got it. Either way, it's super-cool :)

Answer 25

Some awesome work for sure.

Answer 26

yeah i use that part
when i was looking at the pattern
i still don't know how it jumped at me to see that

Answer 27

but
i remember the addends had to be the same as the factors

Answer 28

it was getting on my nerves that teachers were asking is it possible to factor all quadratics

Answer 29

without using the quadratic formula*

Answer 30

i wonder is this sill called using the quadratic formula since this is own the way to proving the quadratic formula
i think it is not
i'm sleepy lol

Answer 31

let me know if you have anymore questions
don't be shy lol

Answer 32

i wouldnt know; i aint got an iphone .... i got a toyota celica circe 1980 tho

Answer 33

yes

Answer 34

that would be totaly awsome