What is the vertex of y = -x^2 + 4 ?

a. (0, -4)
b. (0, -2)
c. (0, 2)
d. (0, 4)

Question

What is the vertex of y = -x^2 + 4 ?

a. (0, -4)
b. (0, -2)
c. (0, 2)
d. (0, 4)

amistre64 · Answer

theres 0 adjustments to the x and +4 adjusted for the y

anonymous · Answer

In general, what is a vertex in terms of a curve like that

anonymous · Answer

Idk.. Lol.

amistre64 · Answer

if we start at (0,0) and adjust x by 0 and y by +4; where do we end up?

anonymous · Answer

If your curve is shaped like U, then the vertex is the bit at the bottom of the U shape, where the curve changes from going down to going up again.

anonymous · Answer

or in this case going up to going down.  just thought i would mention it

anonymous · Answer

Is it D?

amistre64 · Answer

id say its D just by a cursory glance

anonymous · Answer

yup

anonymous · Answer

here is a nice picture. you can see it sits right on (0,4) the highest point on the curve http://www.wolframalpha.com/input/?i=y%3D-x^2%2B4