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Mathematics 18 Online
OpenStudy (anonymous):

How do you complete the square?

OpenStudy (anonymous):

with lines

OpenStudy (anonymous):

I mean with like quadratic equations...

OpenStudy (anonymous):

u add square of half the coefficient of x to both sides.....

OpenStudy (anonymous):

if u give a question I can explain..

OpenStudy (anonymous):

Got it!

OpenStudy (anonymous):

good for u then....☺

OpenStudy (amistre64):

in algebra we are given an equation; quadratic in nature usually; and in order to "complete the square" we can look to geometry: for instance: x^2 +6x + ??? completes the square set it up like this \begin{array}c &&&6/2\ xs\\ &x^2&x&x&x\\ &x&1&2&3\\ 6/2\ xs&x&4&5&6\\ &x&7&8&9\\ \end{array} it take an additional 9 pieces to "complete" the square

OpenStudy (amistre64):

while the geometry is useful to describe what a "complete square" square is; it impractical to use all the time; so we take our lead from it and abstractly construct our square with half of our "x" coefficient; and square it

OpenStudy (anonymous):

example: you have x^2 + 10x + C you want to find C. just simply solve this equation: \[10x = 2x*\sqrt{C}\] i mean, you have to match the second term with this expression ( 2x*sqrt(C) )

OpenStudy (anonymous):

it will give you C = 25. Thats the number you were looking for ;)

OpenStudy (anonymous):

I've found this out by myself when i was in college. It was very useful for my advanced math classes

OpenStudy (anonymous):

I've found this out by myself when i was in college. It was very useful for my advanced math classes

OpenStudy (anonymous):

25 = 5² which is square of half of the coefficient of x as I said !!!

OpenStudy (anonymous):

well.. here is the proof of what you said then. only words doesnt mean anything :p

OpenStudy (anonymous):

could I have another example?

OpenStudy (anonymous):

Just to get it in my brain :)

OpenStudy (amistre64):

abstract: ax^2 +bx +c c = (b/2)^2

OpenStudy (anonymous):

x^2 + 4x + C 4x = 2x*sqrt(C) 2 = sqrt(C) C = 4 so: x^2 + 4x + 4 = perfect square

OpenStudy (amistre64):

thats if a=1 i believe

OpenStudy (anonymous):

thnx!

OpenStudy (anonymous):

Thanks guys!

OpenStudy (amistre64):

no prob

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