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OpenStudy (anonymous):
A bacteria population triples every 12 days. What is a possible equation for its growth?
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OpenStudy (anonymous):
p1= po(x/4) :D.. just a try.. where x is the number of days
OpenStudy (amistre64):
yeah, i couldnt make sense of any of the options you provided :)
OpenStudy (anonymous):
what are the options??
OpenStudy (amistre64):
A*e^(.0196*t) if anything
OpenStudy (anonymous):
can someone tell me if my equation is right?!
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OpenStudy (anonymous):
:( sorry guys. here are the options:
f(t)=a*(1/3)^t/12
f(t)=a*(3)^t
f(t)=a*(3)^t/12
f(t)=a*(3)^-t/12
OpenStudy (anonymous):
third option should be the answer!
OpenStudy (anonymous):
Thank you mashy! :)
OpenStudy (amistre64):
so it was a recursive equation?
OpenStudy (anonymous):
i mean first and 4th option!
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OpenStudy (anonymous):
1st- f(t)=a*(1/3)^t/12
4th- f(t)=a*(3)^-t/12
OpenStudy (anonymous):
fourth is negative t/12
OpenStudy (anonymous):
So... ? Which one?
OpenStudy (anonymous):
3rd is the answer.. arre first and second one are the same (1/3)=3^-1
OpenStudy (anonymous):
K. Thanks mashy :)
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OpenStudy (anonymous):
again i mean't FIRST AND FOURTH.. gosh i dunno whats wrong with me!
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