Question

what is the derivative for the function xy^2 + xln x = 4y for x > 0?

Answer 1

assuming you want the derivative with respect to x..
(1)y^2+2xy(dy/dx)+(1)lnx+x(1/x)=4(dy/dx)
y^2+lnx+1=(4-2xy)(dy/dx)
(y^2+lnx+1)/(4-2xy)=dy/dx

Thar she blows

Answer 2

but

Answer 3

whait is retriceuming

Answer 4

what**

Answer 5

Replace it with "I'm assuming you want.." I don't know how that got replaced by retriceuming

Answer 6

oh ok