Question

Factor completely

12x^2 - 34x + 24

Answer 1

\[2(2x-3)(3x-4)\]

Answer 2

would you check the answer like this?

(2)(2x) + (2)(-3) + (2)(3x) + (2)(-4)

Answer 3

Uhmm, not quite. Two ways,

2*(2x-3)) * (3x-4)
2*[(2x-3)(3x-4)]

Answer 4

would you then FOIL the inner two and multiply that answer by 2?

Answer 5

Yep, that is the second way I had it.

Answer 6

Let me see if I can figure it out, would you let me know if I am right?

Answer 7

forsho

Answer 8

Like this?

(2x)(3x) + (2x)(-4) + (-3)(3x) + (-3)(-4)
6x2 - 8x -9x + 12
2(6x^2 - 8x -9x + 12)
2(6x^2 - 17x + 12)
12x^2 - 34x + 24

Answer 9

It actually came out the same................lol
Didn't think I would get it to do that!

Answer 10

you still here geek?

Answer 11

yep, u got it

Answer 12

tyty, could you possibly help me with one more?

Answer 13

sure, wing it

Answer 14

-18a^2 + 17a + 15

Answer 15

I know that this one has no GCF, and that you have to do something with the first and last numbers to equal the middle one, but I can't figure that out for anything

Answer 16

Here's a start:
-( __ - _ )*( __ + _ )

Answer 17

would I have to rewrite the 17a to 12a + 5a so that I could rewrite the whole thing into -18a^2 + 12a + 5a + 15?

Answer 18

and should I then factor by grouping like this:
2a(9a + 6) + 5(a + 3) ?

Answer 19

you still here geek?