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Mathematics 14 Online
OpenStudy (anonymous):

Typing....

OpenStudy (anonymous):

For a given geometric sequence, the 10th term, \[a _{10}\] , is equal to \[-19\over8\] , and the 14th term, \[a _{10}\] , is equal to -38 . Find the value of the 18th term, \[a _{18}\] . If applicable, write your answer as a fraction.

OpenStudy (anonymous):

ar^9 should be the tenth term

OpenStudy (anonymous):

ar^13 should be 14th term

OpenStudy (anonymous):

Ok buddy.. I'm lost already lol at^9 should be the 10th term? o_O

OpenStudy (anonymous):

divide the 14th by 9th

OpenStudy (anonymous):

yeah that is geometric series thats how is the sequence

OpenStudy (anonymous):

wait check this out http://en.wikipedia.org/wiki/Geometric_series

OpenStudy (anonymous):

Ah I erred in typing

OpenStudy (anonymous):

a_10=-19/8 a_14=-38

OpenStudy (anonymous):

well the nth term of any gs is ar^(n-1)

OpenStudy (anonymous):

yeah you got that right

OpenStudy (anonymous):

now divide the 14th by 10th ar^13 -38 x 8 ---- = r^4 = ----------- ar^9 -19

OpenStudy (anonymous):

r^4 = 16 r = 2

OpenStudy (anonymous):

ar^9 = -19/8 so a = -19/8 *1/512

OpenStudy (anonymous):

Ok Ishaan, I'm going to stop you for a second and tell you, you are WAY too smart.... ok continue

OpenStudy (anonymous):

so the 18th term is ar^17

OpenStudy (anonymous):

thanks shark

OpenStudy (anonymous):

You're very welcome my friend... you're just shooting this off and I'm getting lost just trying to follow >.< math is NOT my friend haha

OpenStudy (anonymous):

substitute the value of a i could write a as -19/8*1/r^9 so 18th term is -19/8 *1/r^9*r^17 -19 r^(17-9) ---- x ------ = -19/8 * r^8 now put r = 2 and you will have your answer 8 math is friend just spend more time you will get way too good at it

OpenStudy (anonymous):

So the common ratio is 2 I've gathered... that wouldn't be -2?

OpenStudy (anonymous):

I'm sorry if my questions are dumb, this is my first time being faced with this type of problem

OpenStudy (anonymous):

a geometric sequence is like multiplying one thing by another over and over. So if advancing from number 10 to 14 you multiply it by 16 (as is the case here) then going from 14 to 18 will be another 16, so it's 16*-38

OpenStudy (anonymous):

no i don't think so not in gp maybe i have done some questions all with absolute values ..it is a good question

OpenStudy (anonymous):

physopholy will correct if anything is done wrong by me he is good

OpenStudy (anonymous):

i may get wrong values but the method is correct

OpenStudy (anonymous):

geometric series are easy. Like 1, 2, 4, 8, 16; 1, 3, 9, 27, 81; 2, 6, 18, 54; 3, 6, 12, 24, 48..these are all different geometric series(es?). You go forward in the sequence by multiplying by whatever number. So if you find the ratio between number 8 and 6, you know the ratio between x and x-2. This is how they give you the answer: by giving you number 10 and 14. Get (#14)/(#10) and you have (#18/#14)

OpenStudy (anonymous):

Ok.. so a_18=-608? So.. since the common ratio is 2... would it be best expressed as -1216/2? or should I just leave the answer as -608 (like I said sorry for dumb questions but this is my first time ever faced with this sort of thing >.< )

OpenStudy (anonymous):

na just leave the answer -608/1 is also fraction

OpenStudy (anonymous):

I see I see... ok.. I think I get it for the most part..

OpenStudy (anonymous):

it is not dumb chris it is very good to get your doubts cleared :D continue this habit you will get better real better like zarkon

OpenStudy (anonymous):

Thank you :) and thank you guys both so much for helping me!

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