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Mathematics 17 Online
OpenStudy (anonymous):

Picture coming...

OpenStudy (anonymous):

OpenStudy (akshay_budhkar):

i think its asking you ros and sor at x=4 right??

OpenStudy (anonymous):

Yes, I believe so.. but when I try I can't work it out.. I come up with -30=/=-8

OpenStudy (anonymous):

(ros)(4)=r(s(4))=r(-30)=+60 (sor)(4)=s(r(4))=s(-8)=-126

OpenStudy (anonymous):

so.. when plugging in r.. would I first solve for r if x=4 or would I just plug the whole equation in?

OpenStudy (anonymous):

first solve x=4 it means put 4 instate of x in equation and solve

OpenStudy (anonymous):

Ok, so I come up with r=-1/2 then I would solve the same for s and use those values in r(s(4))=r(-30)=+60?

OpenStudy (anonymous):

no i think ur doing wrong cause if u put 4 in equation r(x) u will come up with -8 NOT WITH -1/2 and if u put -8 in equation s(x) u will come up with -126

OpenStudy (anonymous):

Shoot... I must be because I came up with r=-1/2 and s=-3/2 >.<

OpenStudy (anonymous):

do it again u will get my answer i think

OpenStudy (anonymous):

OOOHHH Yes... I see what I did wrong

OpenStudy (anonymous):

Ok, I think I got it now.. would you mind checking my final answer as soon as I get it? :/

OpenStudy (anonymous):

no problem what u got the final answer?

OpenStudy (anonymous):

the final answer will be what i got that and post that for you

OpenStudy (anonymous):

Ok... so would ros=-126 then? I guess I don't get it after all >.<

OpenStudy (anonymous):

ros(4) rather

OpenStudy (anonymous):

(ros)(4)=+60 NOT -126

OpenStudy (anonymous):

Oh.. so i got them backward then

OpenStudy (anonymous):

I get it! Ok, so basically, I evaluate the s(x) function for x=4, I take that answer (-30) and plug it into r(x) to come up with 60

OpenStudy (anonymous):

Thank you very much Roh!! I greatly appreciate it, I wish I could give you more than one medal!

OpenStudy (anonymous):

your welcome

OpenStudy (akshay_budhkar):

lol.. my net went chris!! but roh did the job.. i will give him a medal for you..

OpenStudy (anonymous):

Ah, it's ok Akshay, thank you for looking though, and thank you for giving Roh a medal

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