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Mathematics 23 Online
OpenStudy (anonymous):

Aditi bought some b,m,g,p and s.She bought atleast 5 of each.All the numbers bought were distinct.Given that she has bought least number of b,the number of b can be exactly determined if the total number of items bought is atmost.Find the total number of items

OpenStudy (anonymous):

Should there be a number after "atmost"?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

We need to find that

OpenStudy (anonymous):

I don't think it's solvable in that case. The lowest possible number of items purchased is 35, but that doesn't help much as it's based on the assumption that b = 5, but it might not be.

OpenStudy (anonymous):

OpenStudy (anonymous):

I have attached the original question

OpenStudy (anonymous):

Aha, that changes things. Make the assumption that b=5, and the rest are therefore 6, 7, 8, and 9 at their lowest, totalling 35. That is the only way to get 35. If b = 6, then the rest are 7, 8, 9, and 10, totalling 40 at their lowest values. It's possible to get 40 in other ways though, like if b=5, and the rest are 7, 8, 9, and 11. Therefore 40 is not the answer, since b could have several values. Now I ask you, is it possible to get to a total of 39 if b is 6?

OpenStudy (anonymous):

can be possible..

OpenStudy (anonymous):

What would the values of b, m, g, p, and s be in that case?

OpenStudy (anonymous):

it can be 5,6,8,9.11

OpenStudy (anonymous):

Aha! The question states that b is the lowest number. If we say b is 6, then m, g, p, and s have to be more than 6.

OpenStudy (anonymous):

I am keeping b as 5

OpenStudy (anonymous):

But is it possible to get to 39 if b is 6?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

min will be 40

OpenStudy (anonymous):

So the highest you can get where b has only one possible value (b=5) is?

OpenStudy (anonymous):

41 we can get

OpenStudy (anonymous):

At 41, b could equal 5, or 6. What's the highest value where b can only be 5?

OpenStudy (anonymous):

40

OpenStudy (anonymous):

b could be 6 in that case as well, if the values are 6, 7, 8, 9, and 10.

OpenStudy (anonymous):

The point is that b cannot be 6 if the total is 39. The only possible value is 5.

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