Aditi bought some b,m,g,p and s.She bought atleast 5 of each.All the numbers bought were distinct.Given that she has bought least number of b,the number of b can be exactly determined if the total number of items bought is atmost.Find the total number of items
Should there be a number after "atmost"?
no
We need to find that
I don't think it's solvable in that case. The lowest possible number of items purchased is 35, but that doesn't help much as it's based on the assumption that b = 5, but it might not be.
I have attached the original question
Aha, that changes things. Make the assumption that b=5, and the rest are therefore 6, 7, 8, and 9 at their lowest, totalling 35. That is the only way to get 35. If b = 6, then the rest are 7, 8, 9, and 10, totalling 40 at their lowest values. It's possible to get 40 in other ways though, like if b=5, and the rest are 7, 8, 9, and 11. Therefore 40 is not the answer, since b could have several values. Now I ask you, is it possible to get to a total of 39 if b is 6?
can be possible..
What would the values of b, m, g, p, and s be in that case?
it can be 5,6,8,9.11
Aha! The question states that b is the lowest number. If we say b is 6, then m, g, p, and s have to be more than 6.
I am keeping b as 5
But is it possible to get to 39 if b is 6?
no
min will be 40
So the highest you can get where b has only one possible value (b=5) is?
41 we can get
At 41, b could equal 5, or 6. What's the highest value where b can only be 5?
40
b could be 6 in that case as well, if the values are 6, 7, 8, 9, and 10.
The point is that b cannot be 6 if the total is 39. The only possible value is 5.
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