find the of cot of 7pi/2 simple way
\[7\pi/2 = 2\pi + 3\pi/2\] \[\cot 3\pi/2 = undefined\]
oh why is it 2pi + 3pi/2 shouldnt it be 3 and 1/2?
wait scratch that \[\tan 3\pi/2 = undefined\] so \[\cot 3\pi/2 = 0\]
cot 7pi/2 =cos(630)/sin(630) =0
im trying to use a method without calculator
use the unit circle \[\cot 3\pi/2 = \frac{\cos 3\pi/2}{\sin 3\pi/2} = 0\]
pi=180 this means you multiply 7by 180 and divide the result by 2 cot=cos/sin meaning you 'ill have cos630/sin630 =0
ok but can u explain how u got 7pi/2= 2pi + 3pi/2
2pi + 3pi/2 = 4pi/2 + 3pi/2 = 7pi/2
like i know 7/2= 3 1/2 but how does it add with 2pi to get 7/2
I just showed u..
oh ok looks bit confusing what is the purpose of those other fractions if u only need 3pi/2?
I simply answered your question which was "how does it add with 2pi to get 7/2"
better question is why do you have to show 2pi?
tan and cot periodic (repeat values) in pi
oh thanks everyone
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