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Find Derivative: 3xy^2 + y^3 = 8
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with respect to x or y?
derivative with respect to x I am assuming
im not sure says to find in terms of x and y using implicit
now just solve for y'
i got y/2x+y is that correct?
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?
Hold on ,
3xy^2 + y^3 = 8 using product rule 3(2y y' x + y^2) +3y^2 y'=0
now just solve for y'
ohhh with the 3 as a constant I have to put it outside the brackets of the whole derivative of the 3xy^2?
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no, just one bracket 3 multiplies into just one bracket 3(2y y' x + y^2)
right I understand. so is my final answer of y/2x+y correct?
Your answer was very nearly correct amzerz
You are missing a negative I think.
minus
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y' = -y/(2x+y)
right I see that now! thanks!!
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