Question

I need help finding the vertex and axis of symmetry to y=-3x^2

Answer 1

vertex-0,0
axis of symmetry-0

Answer 2

How?

Answer 3

graph it ( i used a graphing calculator)
the point where it turns is the origin
the y axis splits it evenly in half

Answer 4

Thank you. I will probably need more help. I hate College INtermediate Algebra.

Answer 5

Do you want a formula to get the vertex and the axis of symmetry without graphing?

Answer 6

Anyway, here's the formula.

Vertex is (h,k)
The standard form in ax^2+ bx+ c= y or 0

Your equation is y= -3x^2. That makes a= -3, b=0 and c=0 as well.

Formula for h is -b/2a
Substitute and you have

h= -0/2(-3)
h= 0

Formula for k is c-h^2a
Substitute and you have

k= 0-0^2(-3)
k=0

Vertex now is (0,0)

Now the axis of symmetry is equal to x. And x is equal to h.
Substitute and you have

x=0.

Lol, there. Without graphing.
k= 0