Leo held a garage sale. He priced all the items at either a dime or a quarter. His sales totaled less than $5. Which linear inequality would describe the situation? 10d + 25q < 5 0.10d + 0.25q > 5 10d + 25q < 500 10d + 0.25q > 500
Say he had 10 dimes and 4 quarters... how many dollars would he have?
2
ithink not sure bout american currency
You're right. Now look at the left half of the equations above. if d=10, and q=4, which one of them would =2?
none?
a
?? the 1st??
No, sorry. I'm explaining poorly.
yes, make it easy:1 dime=10 cents, 1 quarter=25cents, so 1st one
i think its b
Essaim, you're right. Love math, you aren't.
why
His sales totaled less than $5
yes, less
Because dimes and quarters are 10 CENTS and 25 CENTS, but the right side of the equation is in DOLLARS.
Actually... we're both wrong, sorry.
Because you're right, it is less than (<) so it has to be A or C. But because dimes aren't worth 10 dollars, the answer is C.
so its c??
it cant be c, c is 500
Yes. It is calculated in cents. 10cents*dimes + 25cents*quarters = 500cents. (which is the same as $5)
so I am right?
but 25*.25 is $6.50
25*.25=6.25
Let me try to clarify. Leo gets 25cents for each quarter, and 10cents for each dime. At the end of the day he has less than 500cents ($5).
In mathematical notation, you'd write that as: 10d + 25q < 500 So C is the answer.
ok thxs
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