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Mathematics 17 Online
OpenStudy (anonymous):

http://trickiestofall.blogspot.com/2011/07/never-ask-womens-age-p.html

hero (hero):

Joe, I'm pretty sure you can figure this out

OpenStudy (anonymous):

yeah, im working on it lolol

hero (hero):

I gave up as soon as I realized what I would have to do

OpenStudy (anonymous):

yeah, i want to give up as well, too much work >.>

OpenStudy (anonymous):

alright, im getting the ages of the "women" are 7, 7, and 50, and pastor petersen is 49 yrs old. First prime factor 2450: \[2450 = 2*5*5*7*7\] Then start grouping them to make 3 groups. For example: \[(2*(5*5)(7*7) \Rightarrow 2, 25, 49\] That one be one case where the age of the 3 women multiply up to 2450. After writing out a couple, you will notice that only 2 cases have the same sum. \[(2*5)*(5)*(7*7) \Rightarrow 5, 10, 49 \Rightarrow 64\]and \[(7)*(7)*(2*5*5) \Rightarrow 7, 7, 50 \Rightarrow 64\] Because the teacher couldnt figure out how old the women were with just his age alone, he must be 64 (otherwise he would have solved the problem). Now the next clue is that "The oldest woman is older than Pastor Petersen." Because the teacher was able to figure out the womens ages after that clue, that means the oldest woman must be 50, and the pastor must be 49 (if pastor petersen was younger than 49, the teacher would not have been able to solve the problem.)

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