Question

How would you factor:
49k^3m+42k^2m^2+9km^3

Answer 1

I'd start with taking out \(km\) as being common in all of those terms. What would that leave you with?

Once you have that, you can factorise the remaining quadratic. Hint: Pay attention to the numbers in front of the \(k^2\), and the \(m^2\).

Answer 2

7*7*k*k*k*m+7*4*k*k*m*m+3*3*k*m*m*m

Answer 3

*7*6

Answer 4

If you take out \(km\) as being common, you'll get \[km(49k^2+42km+9m^2)\] Do you notice anything special about 49, and 9?

Answer 5

Other than containing exponents of k and m?

Answer 6

Other than that, yes.

Answer 7

If I said that other numbers of this type were 1, 4, 16, 25, 36. Would it help?