A spring requires a force of 25 N to produce an extension of 2 cm in it. What is the work done in further extending it by 3 cm.
its physics, i guess,.
its application of integration; work section
25.21 / 4
\[\lim\sum F(x)\triangle x\]
c'mon amistre.. he can use formulae as well. k=25/2 and the work done he needs is \[1\div2 \times K \times (a ^{2} - b ^{2})\] a is 5 & b is 2. or else, worry about the integration of k*x .
F(x) = 25x \[\int_{2}^{3}(25x)dx\] maybe?
they can yes; but wheres the fun in that :)
for the record it is a riemann sum as △x approaches zero. thats like the rectangles becoming small enuff that their edges approximate the curve really well. the curve here is a straight line.
25(3^2)/2-25(2^2)/2
the problem isnt fun anyway, its in other word the area under a line of given slope b/w tweo points. or the area of a trapezium. :)
25(9-5)/2 = 25(2) = 50 perhaps?
messed it up lol
25(9-4)/2 lol 25(5)/2 = 125/2 might be better
LOL! All the possible answers are between the numbers 1 and 3 and are in J, joules.
i dont know the conversions right off hand :)
50+12+.5 = 62.5 is the answer I get; but thats prolly in newton-centimeter
a Joule is: 1 newton is displaced through a distance of 1 metre
.03^2 = .0009; ... 25(.0005)/2 = .00625 http://www.wolframalpha.com/input/?i=int%2825x%29dx+from+.02+to+.03
CAN YOU POST YOUR OPTIONS?
IM GONA BREAK OFF THE CAPS KEY LOL
Every time I post my options, my questions get deleted
.625 still aint between 1 and 3
exactly.
if you get it wrong, will it tell you the right answer?
No :/
These are my options 1.3125J 1.876J 2.7121 2.85J
close your eyes, use the force, scream at the top of your lungs while clicking your best guess ....
Dont delete my post now :P
lmao. thats not going to help me much lol. The force isnt always the answer
im thinking i missed a part; something to do with x-someting
Oh the horror. Where's einstein when you need him?! Oh wait its amistre :)
25x(.02+x) maybe? gotta re read up some stuff
ohh.. okay.. Dont take too long :)
25 = 2x F(x) = 25x/2 might be my undoing :)
to get it into newtons tho lets adjust it as this 25x^2 ------ [.02,.03] .04 25(.03^2)/.04 - 25(.02^2)/.04 = .3125 .... doh!! re reading ...
read thru the problem and make sure you havent left out anything or typoed it please
the best i can come up with the given information is .3125
the measurements in the stated problem are simply to small to come up with anything substantive to me
Ohhh I see what you're saying. I guess I'll just go with that answer.
thanks :)
im gonna see if i can interpret this; "What is the work done in further extending it by 3 cm." to mean the over all work done is .5625 J so it cant go higher than that ... srry
Curiousmath, I posted on this in the physics forum, let me know if you still have questions :)
i still have questions :)
I posted it in the physics section too, but that section isnt as popular as this one :)
what's up amistre?
i just looked at your post over there; and its the same information i keep coming up with; so im gonna assume the question is just bad :)
I don't think the answers given are correct, if that's what you are referring to. :)
yep ;)
Join our real-time social learning platform and learn together with your friends!