Question

solve 4x^2-15x=3

Answer 1

i think you need the Pythagorean theorem for this one

Answer 2

What? lol

Answer 3

\[x = [ -b \pm \sqrt{b^2 - 4ac} ] / 2a\]

Answer 4

ax^2 + bx + c = 0

Answer 5

what

Answer 6

That's not pythagorean theorem, that's the quadratic formula

Answer 7

i think you need to use quadratic formula..

a= 4 b= -15 c= -3

Answer 8

a = 4, b = -15, c = -3

Answer 9

ohh im on drugs.. .. haha havent slept

Answer 10

how do i solve it though

Answer 11

just substitute tha values a,b and c in the formula

Answer 12

ok trouble with factors

Answer 13

yea big trouble

Answer 14

thats why u have to use the quadratic formula... do u wnt me to do it or something?

Answer 15

just guide me into doing it its homework and im really confused

Answer 16

\[4x^2 -15x - 3 = 0\]
\[Ok \:\:\:\:I \:\:\:\:\:suggest \:\:\:\:\:\:quadratic \:\:\:\:\:\:\:formula\]

\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
Now, Compare these terms to General Equation
\[ax^ + bx +c =0\]
Now, After this
\[a = 4\]\[b =-15\]\[c=-3\]Now put these into the formula and have Roots : )
If you have any problem then just message me

Answer 17

ya ishaan has done the job well:) good work master!