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Physics 17 Online
OpenStudy (anonymous):

As an electron moves from a high potential to low potential, its electrical potential energy (A) increases or (B) Decrease

OpenStudy (anonymous):

\[\Delta V = \Delta PE/q\] If the potential is less, and the charge q remains the same.. then the electric potential energy must have decreased. B

OpenStudy (anonymous):

it will decrease b coz electric potential always moves to high to low energy potential so the high potential will loss and the charge is always same in case so the ans is b)

OpenStudy (anonymous):

it increases because electron is negative charged

OpenStudy (anonymous):

potential increase, energy decrease. energy has nothing to do with the polarity of the charge.

OpenStudy (anonymous):

it has! positive charge is replled against high potential. -ve charge is attracted towards high potential. this is what happens in a cicuit

OpenStudy (anonymous):

The equation posted above by simplephysics is correct, but the statement following it is not. Let us first rearrange the equation and write: \[\Delta PE = q \Delta V\] Here Delta PE is the change in electrical potential energy, q is the charge, and Delta V is the change in potential. Now, since it is an electron, the charge q is negative. Since it is moving from high potential to low potential, the change in potential Delta V is also negative. So their product, which is the right hand side of the equation, is positive. That means the left hand side, the change in electric potential energy, is positive, which means the electric potential energy increases.

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