Question

In the figure, if PQ = 16 and CD = 30 and PQ is the midsegment of AB and CD with M as its midpoint, then what is the length of a radius of the circle?

Answer

15

8

17

16

Answer 1

looks like 17

Answer 2

yea i think its 17

Answer 3

first join CM

Answer 4

its a pythagoras thing right?

Answer 5

YES

Answer 6

use the pythagorean triangle formed by (1/2)CD and (1/2)PQ. to find hypothenuse

Answer 7

its 17

Answer 8

\[((1/2)(30))^2+((1/2)(16))^2=r^2\]

Answer 9

r=17 as they said