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OpenStudy (anonymous):
solve the equation 9=square root of 3 ^(4x+6)Using complete sentences, explain the strategy used in solving this equation.
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OpenStudy (amistre64):
those online courses are soo nitpicky arent they :)
OpenStudy (anonymous):
yes:(
OpenStudy (amistre64):
hard to parse the equation ..... for me that is
OpenStudy (anonymous):
9=¨3^2
OpenStudy (anonymous):
If you go back and look at the other 2 questions u posted like this, the way to do it will become clear...
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OpenStudy (anonymous):
9=square root of 3 ^(4x+6)
on squaring both sides
=> square of 9 = square of [ square root of 3 ^(4x+6) ]
=> 81 = 3^(4x+6)
=> 3^4 = 3^(4x+6)
=> 4 = 4x+6 //since a^x = a^y .=> x=y
=> 4x+6 = 4
=> 4x = 4-6
=> 4x = -2
=> x = -2/4 // dividing with 4 on both sides
=> x = -1/2
=> x = -0.5
OpenStudy (anonymous):
thank u!!!!!!!!!
OpenStudy (anonymous):
OMG...
OpenStudy (anonymous):
okay i get it now!
OpenStudy (anonymous):
3^2 = 3^(4x+6) SO
2 = 4x +6 -> x = -1
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OpenStudy (anonymous):
i like the way u explained it and put it out thanks!
OpenStudy (anonymous):
u r welcome
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