evaluate 1og base 7 343
can someone please explain how i evaluate this?
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OpenStudy (anonymous):
343 = 7^3...help?
OpenStudy (anonymous):
log7 343\[\log_{7} 343\]
OpenStudy (anonymous):
If u have log_a a^x the answer is x
So log_7 7^3 = 3
OpenStudy (anonymous):
I'd evaluate it with a calculator.
But that basically means the number you raise 7 to to get 343.
OpenStudy (anonymous):
Get it?
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OpenStudy (anonymous):
i dont know how to put it into my caculator
OpenStudy (anonymous):
log_{7} 343 = x
means 7^x=343
OpenStudy (anonymous):
eg log_10 100 = log_10 10^2 = 2
OpenStudy (anonymous):
It is the reverse of the other questions u were doing...
OpenStudy (anonymous):
7 to the what power = 343
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OpenStudy (anonymous):
\[\log7^{343}\]?
OpenStudy (anonymous):
no the 7 is the base
OpenStudy (anonymous):
Quiz
OpenStudy (anonymous):
Calculators only have log base 10 and natural log, which is log base e. So you have to use a sweet math trick to get log base 7.
If you want log_7 343, you enter
(log_10 343) /log_10 7
OpenStudy (anonymous):
2 way you can solve
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OpenStudy (anonymous):
Or in general, log_x y can be entered as
log_10 y / log_10 x
OpenStudy (anonymous):
\[\frac{\log 343}{\log 7}=3\]
OpenStudy (anonymous):
\[x = \log_ay\] means (is the same as saying) \[y=a^x\]