Problem is attached in the picture.
So you have two points to work with...
for slope, y2 - y1 divided by x2 - x1. this is telling us the change in y divided by the change in x.
it's easier to see graphically.
slope = (y2-y1)/(x2-x1) => slope = (-3-4)/(-5-0) = -7/-5 =7/5
once you find the slope, (-3-4) / (-5-0)... you can use the point slope formula...which is y - y1 = m(x-x1) where m is (7/5)
use either one of the points given and put them into the point slope formula...
(0,4) looks easier to work with I guess so...
y - (4) = (7/5)(x-0)
y = (7/5)x + 4 to graph that, just plot the two givin points in the beginning, and draw a straight line through them since this is a linear equation.
y = mx + b is linear y = mx^2 + b is not linear. the square causes a curve.
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