Question

-5√192) -2√243) -8√108) please help subtract terms. Need to show work

Answer 1

You need to find the least common multiple of each value inside the square root.
This is just a tip. If you still doesnt know how to solve please tell me

Answer 2

\[192=2^6\times 3\]
\[243=3^5\]
\[2^2\times 3^3\] this is a start

Answer 3

I have no clue how to do this :[

Answer 4

so for example
\[\sqrt{192}=\sqrt{2^6}\times \sqrt{3}=2^3\times \sqrt{3}=8\times \sqrt{3}\]

Answer 5

is that step clear?

Answer 6

yes, but what do i do with the number infront?

Answer 7

leave it there.

Answer 8

you need to find a common value inside the square root so you can add the roots before.
Is it clear?

Answer 9

first term is
\[-5\times 8\times \sqrt{3}=-40\sqrt{3}\]

Answer 10

i haven't touched this stuff in like 4 months.

Answer 11

second term is
\[-2\times 3^2\times \sqrt{3}=-18\sqrt{3}\]

Answer 12

third term is
\[-8\times 2\times 3\times \sqrt{3}=-48\sqrt{3}\]

Answer 13

then they are like terms so you can combine them

Answer 14

you need to leave only a 3 inside each square root.

3 is the least common multiple number.

so it must be something like:

−5×(8×√3) , where (8×√3) = √192.
Got it?

Answer 15

yes thank you so much!

Answer 16

@diego the point is not that 3 is the least "common multiple". the point is that when you write each in simplest radical form you end up with three terms that include
\[\sqrt{3}\]
your answer is of course right