Okay, so I am suppose to solve for x in this problem, but I dont understand the answer.
Problem x^2+14x+4=0
Answer -7-3sqrt5, -7-3sqrt5
Can anyone explain?

Question

vijay · Answer

$$x ={ -b \pm \sqrt{b ^{2} - 4ac}}     / 2a $$

vijay · Answer

b = 14, a = 1 and c = 4, substitute into the above equation, u will fin x.

anonymous · Answer

$$x^2+14x+4=0$$
$$x^2+14x=-4$$
$$(x+7)^2=-4+7^2$$
$$(x+7)^2=45$$
$$x+7=\pm\sqrt{45}$$
$$x=-7\pm\sqrt{45}$$
 and 
$$\sqrt{45}=\sqrt{9\times 5}=3\sqrt{5}$$ so answer is
$$x=-7\pm 3\sqrt{5}$$

anonymous · Answer

you can use quadratic formula too, but you will have a raft of simplification to do at the end

anonymous · Answer

But how is it separated by a coma? and your answer only has one set of numbers.

anonymous · Answer

i wrote 
$$\pm$$ meaning both the positive and negative radical

anonymous · Answer

oh :)
Your answer is still different than the answer above

anonymous · Answer

typo there. it is 
$$x=-7+3\sqrt{5}$$
$$x=-7-3\sqrt{5}$$

anonymous · Answer

nevermind lol

anonymous · Answer

that is what the plus/minus indicates. two numbers

anonymous · Answer

oh. Sorry. It's a new day; therefor I'm basically learning this all over again lol