Problem is attached in the picture.
its a "system" so it means that if there is only one solution to it they both have the same values for x and y.... in other words, they both intersect at that point (x,y) on the graph
do i plug the number in the parentheses into the equations?
To solve it you need the x terms and the y terms on the same side... NO, no pluging in here because those are just numbers to show you what equations they are, eq1 and eq2
so bring the -9y over to the other side in eq(2) as a +9y with the x
then the equations will look like...
x + 9y = 3.........and........ x + 9y = 6
but as you can see, not so clearly, nothing works for x and y here... there is no solution.
you can multiply eq2 now by (-1) on both sides and see it like this...
ooooo so its no solution?
x + 9y = 3 -x -9y = -6 ------------- 0 + 0 = -3 <--------- zero does not = 3 so... NO SOLUTION
Yay , thanks. You've been alot of help lol.
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