Question

Solve the radical equation √18x-9=x+4

Answer 1

\[\sqrt{18}x-x=4+9\]
\[x(1-\sqrt{18})=13\]
\[x=\frac{13}{1-\sqrt{18}}\]
\[x=\frac{13(1+\sqrt{18})}{1-18}=\frac{13+13\sqrt{18}}{-17}\]

Answer 2

but somehow i think you meant to write
\[\sqrt{18x-9}=x+4\]

Answer 3

Yes I did.

Answer 4

square both sides

Answer 5

\[(\sqrt{18x-9})^2=(x+4)^2\]
\[18x-9=(x+4)(x+4)\]
\[18x-9=x^2+4x+4x+16\]
\[18x-9=x^2+8x+16\]
\[18x-18x-9+9=x^2+8x-18x+16+9\]
\[0=x^2-10x+25\]

Answer 6

does this help?

Answer 7

0=(x-5)(x-5)
x=5

Answer 8

Yes.