How many steps are required to break an m x n bar of chocolate into 1 x 1 pieces?
You can break an existing piece of chocolate horizontally or vertically.
You cannot break two or more pieces at once (so no cutting through stacks).
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OpenStudy (anonymous):
stacks ?
OpenStudy (anonymous):
meant rows,eh?
OpenStudy (anonymous):
You can't place one piece on top of the other, and break them both with one move.
OpenStudy (anonymous):
i like this problem :)
OpenStudy (anonymous):
LIKE!
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OpenStudy (anonymous):
Anyone got an answer for me?
OpenStudy (anonymous):
is it ok if i say it? i was kinda hoping someone else would get it.
OpenStudy (anonymous):
Doesn't look like anyone else is interested :)
OpenStudy (anonymous):
how can people not be interested? its a bar of chocolate!
OpenStudy (anonymous):
Maybe they're lactose intolerant?
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OpenStudy (anonymous):
It might be soya chocolate people!
OpenStudy (anonymous):
or like icecream ?
myininaya (myininaya):
it takes (m times n) times
OpenStudy (anonymous):
Incorrect I'm afraid!
myininaya (myininaya):
lol
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OpenStudy (anonymous):
mn thats what you need
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
m n^2
OpenStudy (anonymous):
It's close, but it's no cigar.
OpenStudy (anonymous):
m are rows right then m^2 n
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OpenStudy (anonymous):
Your first answer was the closest.
OpenStudy (anonymous):
you guys have the right idea for sure. (when saying m*n)
OpenStudy (anonymous):
m (n-1) or (m-1)n
OpenStudy (anonymous):
Nope, I'm afraid not.
OpenStudy (anonymous):
ok let me do this 3x3
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OpenStudy (anonymous):
we need three column cut
OpenStudy (anonymous):
You need 2 columns cut, not 3.
OpenStudy (anonymous):
at the bottom
myininaya (myininaya):
(m-1)+(n-1)
OpenStudy (anonymous):
Well 2 cuts to make 3 columns.
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OpenStudy (anonymous):
yeah sorry 2 thats what i meant
OpenStudy (anonymous):
then 3 row cut
OpenStudy (anonymous):
@myininaya nope >.<
OpenStudy (anonymous):
anyway unless m=n it depend on how you break it. ... good clue ?
myininaya (myininaya):
wait why
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OpenStudy (anonymous):
It doesn't depend on how you break it.
OpenStudy (anonymous):
As long as all your breaks are straight vertical or horizontal lines.
myininaya (myininaya):
if we have a 3*2 then we need 2 horizontal cuts and 1 vertical cut
if we have a 4*6 then we need 3 horizontal cuts and 5 vertical cuts
OpenStudy (anonymous):
m(n-1) this should be it
(m-1)(n-1)x n
OpenStudy (anonymous):
this should be correct
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OpenStudy (anonymous):
If you have a 3*2, you need 5 breaks. Remember you can only break one piece at a time. You are incorrect Ishaan!
myininaya (myininaya):
i get 3 breaks how do you get 5?
OpenStudy (anonymous):
Once you make your 2 vertical cuts, you have 3 pieces which have to be cut separately. You can't cut all 3 pieces with one cut.
myininaya (myininaya):
ok
myininaya (myininaya):
i really dont know im confused
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OpenStudy (anonymous):
my answer is correct i buy 3x3 bar ( i don't like 2x3 )
OpenStudy (anonymous):
I have a hint i want to give but i think it pretty much solves the problem =/
myininaya (myininaya):
so would we need 60 for a 4*6?
OpenStudy (anonymous):
You would need 23 for a 4x6
myininaya (myininaya):
lol
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OpenStudy (anonymous):
Think of it like this, if you have an mxn bar, you want to end up with m*n pieces. No matter where you break it the first time, you will end up with 2 pieces afterwards.
I deleted over half of my hint lol
OpenStudy (anonymous):
The same can be said of any break. A single break on any piece will create one \(extra\) piece.
OpenStudy (anonymous):
m(n-1) + n-1
OpenStudy (anonymous):
hows this
OpenStudy (anonymous):
i mean
m(n-1) + m-1
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OpenStudy (anonymous):
LOL
OpenStudy (anonymous):
That will work for square pieces only Ishaan, when m and n are equal.
OpenStudy (anonymous):
Ah, didn't read your second one
Expand out the brackets.
OpenStudy (anonymous):
i say ishaans formula works all the time
OpenStudy (anonymous):
no it works for 4x6
m(n-1) + m-1
4(6-1) + 4-1
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myininaya (myininaya):
(m-1)+((n-1)*m) let me see if this works
OpenStudy (anonymous):
i got it
OpenStudy (anonymous):
myininaya's works too.
OpenStudy (anonymous):
Yeah you said "m(n-1) + n-1" first, which I replied to. Your second one is correct, but you can make it simpler.
OpenStudy (anonymous):
ahah yeah myininaya works too
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myininaya (myininaya):
yep i tested it on another one
OpenStudy (anonymous):
mn -1
OpenStudy (anonymous):
m*n-1
OpenStudy (dumbcow):
(m*n)-1
because you dont have to break the last piece
OpenStudy (anonymous):
I expected this question to end way earlier XD
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