Question

u-5/2u-4 divided by u+3/3u+6 x times 6/3u-15= ?
(It's a rational expression; need some help simplifying.)

Answer 1

Never mind the the x is the same as times...

Answer 2

So since u-5/2u-4 is being divided by u+3/3u+6 we must reciprocate u+3/3u+6 and multiply it with u-5/2u-4 to get
u-5(3u+6)/2u-4(u+3) *6/3u-15

Answer 3

Yes...

Answer 4

Now we must use the FOIL method to simplify our first fraction. We should get
3u^2+6u-15u-30/2u^2+6u-4u-12
Combining like terms, our first fraction should be
3u^2-9u-30/2u^2+2u-12
now we can factor 3 out of our numerator and 2 out of our denominator to get
3(u^2-3u-10)/2(u^2+u-6)

Answer 5

yes...and?

Answer 6

~EDIT~
Now we multiply that fraction with 6/3u-15
To get 3(u^2-3u-10)/2(u^2+u-6) * 6/3u-15
Notice we can factor 3 out of the denominator of the second fraction and cancel our threes so our result is
(u^2-3u-10)/2(u^2+u-6)* 6/u-5
Now we multiply our numerators and denominators to get
6(u^2-3u-10)/2(u^2+u-6)(u-5)
Next we factor out our numerator and denominator to see if anything cancels
6(u-5)(u+2)/2(u+2)(u-3)(u-5)
Turns out the (u+5) and (u+2) binomials cancel so our new expression is
6/2(u-3)
The coefficients of 6 and 2 simplify to 3 and our final answer fully simplified is
3/(u-3)
Let me know if you have any questions

Answer 7

Thank you for clarifying how to simplify that.

Answer 8

I do have another problem though, if you could possibly help me out with it.

Answer 9

No problem. Just wanted to make sure you knew how to get the answer rather than just blatantly giving an answer with little or no reason to back it up.

Answer 10

7t^2-28t/2t^2-5t-12 times 6t^2-t-15/49t^3