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if (cosx)^2 = (1+cos2x)/2 then (secx)^2=2/(1+cos2x) true?
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yeh
this question is telling me to "complete the identity" of (secx)^2-(tanx)^2=? any thoughts?
i can put them all in terms of cosine and fig it out, yeh?
sec^2x=1+tan^2x
damn you're good
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lol :D
so 1+tan^2x-tan^2x =..... 1? LOL
obviously... the tan^2x cancels nd ur left wit 1 so 1=1 thats right.... the answer is (secx)^2-(tanx)^2=1
sorry. did the ... to imply i'm an idiot, pre-obviously :D
u can derive all that from sin^2x+cos^2x=1 if u divide them all by cos^2x u get the equation i wrote
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