the difference of like logs is equal to a log of their division (order sensitive!)
OpenStudy (anonymous):
ok thanks dude
OpenStudy (anonymous):
loga-logb = log(a/b)
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OpenStudy (anonymous):
loga+logb = log(ab)
OpenStudy (anonymous):
SAME base, order sensitive in division
OpenStudy (anonymous):
ohh ok
OpenStudy (anonymous):
how about......... 5logx-4log(x-3)
OpenStudy (anonymous):
you better give me a medal :P
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OpenStudy (anonymous):
how do i give it to you?
OpenStudy (anonymous):
ill give as many as i can though,..lol
OpenStudy (anonymous):
= logx^5-log(x-3)^4 = log((x^5)/((x-3)^4)
OpenStudy (anonymous):
how can i give you more medals? =P
OpenStudy (anonymous):
coefficients are the same as exponents because logs are power functions, so that log(base a)b=c is equivalent to a^c=b
log means what i raise the base to to get the number "what do i raise a to to get b" = c
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OpenStudy (anonymous):
new medal = new thread
OpenStudy (anonymous):
so 1 medal per thing you type?
OpenStudy (anonymous):
factor 9x^4 - y^6
OpenStudy (anonymous):
ask new questions in new threads :D
OpenStudy (anonymous):
ok answer them for me???
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