Question

Janice has 8 DVD case on a shelf, one for each season of her favorite TV show .Her brother accidentally knocks them off the shelf onto the floor .When her brother puts them back on the shelf ,he does not pay attention to the season numbers and puts the case back on the shelf randomly .Find each probability
1)P(season 5 in the correct position)
2)P(season 1 and 8 in the correct position)

Answer 1

1)\[\frac{1}{8}\]

Answer 2

2)
\[\frac{1}{8}\times \frac{1}{7}\]

Answer 3

can you help me more?

Answer 4

P(season 1 through 4 in the correct position)

Answer 5

sure

Answer 6

P(all even number seasons followed by all odd-numbered seasons)

Answer 7

we reason as follows: probability season one is in correct spot is 1/8
then the probability season two is in the correct spot GIVEN season one is is 1/7

Answer 8

P(all even number seasons in the correct position)

Answer 9

P(season 5 through 8 in ant order followed by seasons 1 through 4 in any oder)

Answer 10

and so on. then multiply to get
\[\frac{1}{8}\times \frac{1}{7}\times \frac{1}{6}\times \frac{1}{5}\]

Answer 11

which one?

Answer 12

that was answer to P(season 1 through 4 in the correct position)

Answer 13

P(all even number seasons followed by all odd-numbered seasons)
?

Answer 14

all even numbers in correct position. only one way to do that, but then 4! ways to arrange the other ones so that is

\[\frac{4!}{8!}=\frac{1}{8\times 7\times 6\times 5}\]

Answer 15

P(season 5 through 8 in ant order followed by seasons 1 through 4 in any oder)
\[\frac{4!\times 4!}{8!}\]

Answer 16

hope it is clear how i am getting these

Answer 17

all even numbers followed by all odd numbers
\[\frac{4}{8}\times \frac{3}{7}\times \frac{2}{6}\times \frac{1}{5}\] and once you have all the even numbers first the odds must follow

Answer 18

got this?