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Mathematics 19 Online
OpenStudy (anonymous):

Factor completely: 3w^2 +10w +8 = (? ?) (? ?)

OpenStudy (saifoo.khan):

\[\Huge (w+2) (3 w+4)\]

OpenStudy (katrinakaif):

3w + 4) (w + 2)

OpenStudy (anonymous):

agree!!!

OpenStudy (anonymous):

I had all the right numbers, but can't figure out the rhyme or reason for the order. Any tips? Thank you all

OpenStudy (anonymous):

order isnt importand

OpenStudy (saifoo.khan):

umm, there is noprob in order.

OpenStudy (katrinakaif):

You dont need the order in factoring.

OpenStudy (anonymous):

hmmm... then how come an answer of (w+4)(3w+2) is wrong?

OpenStudy (katrinakaif):

That order doesnt matter ;)

OpenStudy (anonymous):

you changed the matter in the brackets not the order of brackets

OpenStudy (katrinakaif):

Nailed it

OpenStudy (saifoo.khan):

Look, as u r going to multiply.. it will become: 3w^2 + 2w + 12w + 8 3w^2 + 12w + 8

OpenStudy (anonymous):

3w^2+6w+4w+8 3w(w+2)+4(w+2) (3w+4)(w+2)

OpenStudy (anonymous):

that is the complete solution

OpenStudy (saifoo.khan):

yes, so Sungirl... your factorization was incorrect.

OpenStudy (katrinakaif):

(w+4)(3w+2) this OR (3w + 2) (w +4)..it doesnt matter What DOES matter if its (w + 2) (3w +4) INSTEAD of (w +4)(3w + 2)

OpenStudy (anonymous):

I need to keep working on this apparently, I'm taking one little wrong step somewhere. I'm using the FOIL method, maybe it's not the way to go but the way that's being taught right now...

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