What is the equation of the line passing through (0, 2) and perpendicular to the line y = 4x – 3 in slope-intercept form?
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OpenStudy (anonymous):
0=x,2=y
2=4(0)+b
OpenStudy (anonymous):
wait... perp, not parallel
OpenStudy (anonymous):
2=-1/4(0)+b
OpenStudy (anonymous):
y = –4x + 3
y = 4x + 2
y = -1/4x + 2
y = 1/4x + 2
OpenStudy (anonymous):
2=0+b
2=b
y=-1/4 x+2
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OpenStudy (anonymous):
wait-ur original line was 4x+3, right?
OpenStudy (anonymous):
The firts thing that you need to do is sketch the graph
then second thing u must know is that for the lines to be parrallel their slopes
hava to multiplied "-1"= m1*m2=-1
then you have to find a line function with slope of -1/4 that crosses the point(0,2)
OpenStudy (amistre64):
the first thing you need to do .....
realize that they give you slope intercept form, and give you a new intercept number and tell you to modify the slope to perp
OpenStudy (amistre64):
th3 perp of 4 is NOT 1/4 , ill assume thats a typo tho
OpenStudy (amistre64):
just like mines a typo lol
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OpenStudy (anonymous):
what??
OpenStudy (amistre64):
your slope of 1/4 is in error.
the slope of a perpendicular lines have a product of -1
4 * (1/4) NOT= -1
OpenStudy (amistre64):
4*p = -1
p = -1/4 is the slope of any perp line to the original equation