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would 23√23/23 be √23?
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Yes
You can cancel all factors that the numerator and denominator have in common.
can you multiply \[\sqrt{11}\] by \[\sqrt{3}\]
Certainly: \[\sqrt{a} \cdot \sqrt{b} = \sqrt{a\cdot b}\]
could i then divide \[\sqrt{33}\] by 3 ? or no because theres no \[\sqrt{?}\]
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Correct. \[\frac{\sqrt{33}}{3} \ne \sqrt{\frac{33}{3}}\]
You cannot do that division.
do you mean 23times by the square root of (23/23)? b/c 23/23 is just 1, so then the answer would be 23, not root 23
YES
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